例子
代码如下$data = "{"type":"news", "offset":50, "count":20 }";
$access_token = "0erCbg(此处省略112个字)DZrOR0PJBFLhAHAMQW";
$url = "https://api.weixin.qq.com/cgi-bin/material/batchget_material?access_token=".$access_token;
// 发送数据
$ch = curl_init();
$timeout = 300;
curl_setopt($ch, CURLOPT_URL, $url);
// curl_setopt($ch, CURLOPT_REFERER, "http://www.111cn.net/"); // 伪装来路
curl_setopt($ch, CURLOPT_POST, true);
curl_setopt($ch, CURLOPT_POSTFIELDS, $data);
curl_setopt($ch, CURLOPT_RETURNTRANSFER, 1);
curl_setopt($ch, CURLOPT_CONNECTTIMEOUT, $timeout);
curl_setopt($ch, CURLOPT_SSL_VERIFYPEER, FALSE); // URL为SSL时添加这行可解决页面空白
$rs = curl_exec($ch);
curl_close($ch);
// 输出
$rs = json_decode($rs);
echo "
";";
print_r($rs);
echo "
例子
方法1感觉也很笨拙，似乎也很难满足我的需求，最后忘记在哪个英文网站上找到了下面这个方法：
代码如下 function do_post_request($url, $data, $optional_headers = null){
$params = array("http" => array(
"method" => "POST",
"content" => $data
));
if ($optional_headers !== null) {
$params["http"]["header"] = $optional_headers;
}
$ctx = stream_context_create($params);
$fp = @fopen($url, "rb", false, $ctx);
if (!$fp) {
throw new Exception("Problem with $url, $php_errormsg");
}
$response = @stream_get_contents($fp);
if ($response === false) {
throw new Exception("Problem reading data from $url, $php_errormsg");
}
return $response;
}
试用了一下，感觉效果非常好，简洁，通用，而且返回的内容仅仅是Body中内容
【phpstudy】PHP 使用 POST 方式向https发送数据请求
http://m.bbyears.com/shujuku/101052.html
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