shell命令|Shell使用Epoch进行日期时间转换和计算的几个小函数

时间:2020-12-09  来源:php函数  阅读:

核心代码

当你遇到一个date命令不给力的系统时,可以试试这几个小函数。 #日期转天数 function date2days {   echo "$*" | awk \"{     z=int((14-$2)/12); y=$1+4800-z; m=$2+12*z-3;     j=int((153*m+2)/5)+$3+y*365+int(y/4)-int(y/100)+int(y/400)-2472633;     print j   }\" } date2days `echo "2010-08-18 18:59:19" | sed \"s/-/ /g;s/:/ /g\"` #天数转日期 function days2date {   echo "$1" | awk \"{     a=$1+2472632; b=int((4*a+3)/146097); c=int((-b*146097)/4)+a;      d=int((4*c+3)/1461); e=int((-1461*d)/4)+c; m=int((5*e+2)/153);     dd=-int((153*m+2)/5)+e+1; mm=int(-m/10)*12+m+3; yy=b*100+d-4800+int(m/10);     printf ("%4d-%02d-%02d\\n",yy,mm,dd)   }\" } days2date 14839 #日期转分钟 function date2minutes {   echo "$*" | awk \"{     z=int((14-$2)/12); y=$1+4800-z; m=$2+12*z-3;     j=int((153*m+2)/5)+$3+y*365+int(y/4)-int(y/100)+int(y/400)-2472633;     j=j*1440+$4*60+$5     print j   }\" } date2minutes `echo "2010-08-18 18:59:19" | sed \"s/-/ /g;s/:/ /g\"` #分钟转日期 function minutes2date {   echo "$1" | awk \"{     i=$1; nn=i%60; i=int(i/60); hh=i%24; dd=int(i/24); i=int(i/24);     a=i+2472632; b=int((4*a+3)/146097); c=int((-b*146097)/4)+a;      d=int((4*c+3)/1461); e=int((-1461*d)/4)+c; m=int((5*e+2)/153);     dd=-int((153*m+2)/5)+e+1; mm=int(-m/10)*12+m+3; yy=b*100+d-4800+int(m/10);     printf ("%4d-%02d-%02d %02d:%02d\\n",yy,mm,dd,hh,nn)   }\" } minutes2date 21369299 #日期转秒数 function date2seconds {   echo "$*" | awk \"{     z=int((14-$2)/12); y=$1+4800-z; m=$2+12*z-3;     j=int((153*m+2)/5)+$3+y*365+int(y/4)-int(y/100)+int(y/400)-2472633;     j=j*86400+$4*3600+$5*60+$6     print j   }\" } date2seconds `echo "2010-08-18 18:59:19" | sed \"s/-/ /g;s/:/ /g\"` #秒数转日期 function seconds2date {   echo "$1" | awk \"{     i=$1; ss=i%60; i=int(i/60); nn=i%60; i=int(i/60); hh=i%24; dd=int(i/24); i=int(i/24);     a=i+2472632; b=int((4*a+3)/146097); c=int((-b*146097)/4)+a;      d=int((4*c+3)/1461); e=int((-1461*d)/4)+c; m=int((5*e+2)/153);     dd=-int((153*m+2)/5)+e+1; mm=int(-m/10)*12+m+3; yy=b*100+d-4800+int(m/10);     printf ("%4d-%02d-%02d %02d:%02d:%02d\\n",yy,mm,dd,hh,nn,ss)   }\" } seconds2date 1282157959 #日期转毫秒 function date2milliseconds {   echo "$*" | awk \"{     z=int((14-$2)/12); y=$1+4800-z; m=$2+12*z-3;     j=int((153*m+2)/5)+$3+y*365+int(y/4)-int(y/100)+int(y/400)-2472633;     j=j*86400+$4*3600+$5*60+$6     printf ("%d%s\\n",j,$7)   }\" } date2milliseconds `echo "2010-08-18 18:59:19.073" | sed \"s/-/ /g;s/:/ /g;s/\\./ /g\"` #毫秒转日期 function milliseconds2date {   echo "$1" | awk \"{     i=$1; ms=i%1000; i=int(i/1000); ss=i%60; i=int(i/60); nn=i%60; i=int(i/60); hh=i%24; dd=int(i/24); i=int(i/24);     a=i+2472632; b=int((4*a+3)/146097); c=int((-b*146097)/4)+a;      d=int((4*c+3)/1461); e=int((-1461*d)/4)+c; m=int((5*e+2)/153);     dd=-int((153*m+2)/5)+e+1; mm=int(-m/10)*12+m+3; yy=b*100+d-4800+int(m/10);     printf ("%4d-%02d-%02d %02d:%02d:%02d.%03d\\n",yy,mm,dd,hh,nn,ss,ms)   }\" } milliseconds2date 1282157959073

应用实例:

计算今天的N天之后的日期

#!/bin/bash function date2days {   echo "$1 $2 $3" | awk \"{     z=int((14-$2)/12); y=$1+4800-z; m=$2+12*z-3;     j=int((153*m+2)/5)+$3+y*365+int(y/4)-int(y/100)+int(y/400)-2472633;     print j   }\" } function days2date {   echo "$1" | awk \"{     a=$1+2472632; b=int((4*a+3)/146097); c=int((-b*146097)/4)+a;      d=int((4*c+3)/1461); e=int((-1461*d)/4)+c; m=int((5*e+2)/153);     dd=-int((153*m+2)/5)+e+1; mm=int(-m/10)*12+m+3; yy=b*100+d-4800+int(m/10);     printf ("%4d%02d%02d\\n",yy,mm,dd)   }\" } year=`date +%Y`; month=`date +%m`; day=`date +%d` days=`date2days $year $month $day` N=5 let days-=$N days2date $days

计算某天的N天之后的日期

#!/bin/bash function date2days {   echo "$1 $2 $3" | awk \"{     z=int((14-$2)/12); y=$1+4800-z; m=$2+12*z-3;     j=int((153*m+2)/5)+$3+y*365+int(y/4)-int(y/100)+int(y/400)-2472633;     print j   }\" } function days2date {   echo "$1" | awk \"{     a=$1+2472632; b=int((4*a+3)/146097); c=int((-b*146097)/4)+a;      d=int((4*c+3)/1461); e=int((-1461*d)/4)+c; m=int((5*e+2)/153);     dd=-int((153*m+2)/5)+e+1; mm=int(-m/10)*12+m+3; yy=b*100+d-4800+int(m/10);     printf ("%4d%02d%02d\\n",yy,mm,dd)   }\" } year=2010; month=01; day=20 days=`date2days $year $month $day` let days+=5 days2date $days

计算上一个星期的全部日期

#!/bin/bash function date2days {   echo "$1 $2 $3" | awk \"{     z=int((14-$2)/12); y=$1+4800-z; m=$2+12*z-3;     j=int((153*m+2)/5)+$3+y*365+int(y/4)-int(y/100)+int(y/400)-2472633;     print j   }\" } function days2date {   echo "$1" | awk \"{     a=$1+2472632; b=int((4*a+3)/146097); c=int((-b*146097)/4)+a;      d=int((4*c+3)/1461); e=int((-1461*d)/4)+c; m=int((5*e+2)/153);     dd=-int((153*m+2)/5)+e+1; mm=int(-m/10)*12+m+3; yy=b*100+d-4800+int(m/10);     printf ("%4d%02d%02d\\n",yy,mm,dd)   }\" } function date2week {   echo "$1 $2 $3" | awk \"{     z=int((14-$2)/12); y=$1+4800-z; m=$2+12*z-3;     dow=(int((153*m+2)/5)+$3+y*365+int(y/4)-int(y/100)+int(y/400)-2472629)%7;     print dow   }\" } year=`date +%Y`; month=`date +%m`; day=`date +%d` days=`date2days $year $month $day` week=`date2week $year $month $day` let dateEnd=$days-$week-1 let dateBegin=$dateEnd-6 for ((i=$dateBegin;i<=$dateEnd;i++)); do   days2date $i done

日期时间转换成毫秒

function date2milliseconds {   echo "$*" | awk \"{     z=int((14-$2)/12); y=$1+4800-z; m=$2+12*z-3;     j=int((153*m+2)/5)+$3+y*365+int(y/4)-int(y/100)+int(y/400)-2472633;     j=j*86400+$4*3600+$5*60+$6     print j$7   }\" } date2milliseconds `echo "2010-08-18 18:59:19.073" | /usr/xpg4/bin/awk -F\"[:.-]+\" \"$1=$1\"`

日期时间转换成秒

function date2seconds {   echo "$*" | awk \"{     z=int((14-$2)/12); y=$1+4800-z; m=$2+12*z-3;     j=int((153*m+2)/5)+$3+y*365+int(y/4)-int(y/100)+int(y/400)-2472633;     j=j*86400+$4*3600+$5*60+$6     print j   }\" } date2seconds `echo "2010-07-21 00:00:00" | sed \"s/-/ /g;s/:/ /g\"`

判断一个数字是否为合法日期

function date2days {   echo "$*" | awk \"{     z=int((14-$2)/12); y=$1+4800-z; m=$2+12*z-3;     j=int((153*m+2)/5)+$3+y*365+int(y/4)-int(y/100)+int(y/400)-2472633;     print j   }\" } function days2date {   echo "$1" | awk \"{     a=$1+2472632; b=int((4*a+3)/146097); c=int((-b*146097)/4)+a;      d=int((4*c+3)/1461); e=int((-1461*d)/4)+c; m=int((5*e+2)/153);     dd=-int((153*m+2)/5)+e+1; mm=int(-m/10)*12+m+3; yy=b*100+d-4800+int(m/10);     printf ("%4d%02d%02d\\n",yy,mm,dd)   }\" } num1=20105050 num2=20101001 arg1=`echo "$num1" | sed -r \"s/(....)(..)(..)/\\1 \\2 \\3/g\"` arg2=`echo "$num2" | sed -r \"s/(....)(..)(..)/\\1 \\2 \\3/g\"` days1=`date2days $arg1` date1=`days2date $days1` days2=`date2days $arg2` date2=`days2date $days2` [ "$num1" -eq "$date1" ] && echo "$num1 is valid date" || echo "$num1 is invalid date" [ "$num2" -eq "$date2" ] && echo "$num2 is valid date" || echo "$num2 is invalid date"

计算10分钟之前的时间

function date2minutes {   echo "$*" | awk \"{     z=int((14-$2)/12); y=$1+4800-z; m=$2+12*z-3;     j=int((153*m+2)/5)+$3+y*365+int(y/4)-int(y/100)+int(y/400)-2472633;     j=j*1440+$4*60+$5     print j   }\" } function minutes2date {   echo "$1" | awk \"{     i=$1; nn=i%60; i=int(i/60); hh=i%24; dd=int(i/24); i=int(i/24);     a=i+2472632; b=int((4*a+3)/146097); c=int((-b*146097)/4)+a;      d=int((4*c+3)/1461); e=int((-1461*d)/4)+c; m=int((5*e+2)/153);     dd=-int((153*m+2)/5)+e+1; mm=int(-m/10)*12+m+3; yy=b*100+d-4800+int(m/10);     printf ("%4d-%02d-%02d %02d:%02d\\n",yy,mm,dd,hh,nn)   }\" } now=`date "+%Y-%m-%d %H:%M" | sed \"s/-/ /g;s/:/ /g\"` minutes=`date2minutes $now` let minutes-=10 minutes2date $minutes

计算指定日期和当前系统日期之家相差多少天

#!/bin/bash function date2days {   echo "$*" | awk \"{     z=int((14-$2)/12); y=$1+4800-z; m=$2+12*z-3;     j=int((153*m+2)/5)+$3+y*365+int(y/4)-int(y/100)+int(y/400)-2472633;     print j   }\" } echo "Enter your date:" read input InpuDays=$(date2days ${input:0:4} ${input:4:2} ${input:6:2}) SysDays=$(date2days `date +"%Y %m %d"`) let result=$InpuDays-$SysDays echo $result
#./test.sh Enter your date: 20110605 25

上个星期周一的日期

#!/bin/bash function date2days {   echo "$1 $2 $3" | awk \"{     z=int((14-$2)/12); y=$1+4800-z; m=$2+12*z-3;     j=int((153*m+2)/5)+$3+y*365+int(y/4)-int(y/100)+int(y/400)-2472633;     print j   }\" } function days2date {   echo "$1" | awk \"{     a=$1+2472632; b=int((4*a+3)/146097); c=int((-b*146097)/4)+a;      d=int((4*c+3)/1461); e=int((-1461*d)/4)+c; m=int((5*e+2)/153);     dd=-int((153*m+2)/5)+e+1; mm=int(-m/10)*12+m+3; yy=b*100+d-4800+int(m/10);     printf ("%4d%02d%02d\\n",yy,mm,dd)   }\" } function date2week {   echo "$1 $2 $3" | awk \"{     z=int((14-$2)/12); y=$1+4800-z; m=$2+12*z-3;     dow=(int((153*m+2)/5)+$3+y*365+int(y/4)-int(y/100)+int(y/400)-2472629)%7;     print dow   }\" } year=`date +%Y`; month=`date +%m`; day=`date +%d` days=`date2days $year $month $day` week=`date2week $year $month $day` let date=$days-$week-7 days2date $date

shell命令|Shell使用Epoch进行日期时间转换和计算的几个小函数

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